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3(x+-1)+7=4x+2+-3(2+-1x)
We move all terms to the left:
3(x+-1)+7-(4x+2+-3(2+-1x))=0
We add all the numbers together, and all the variables
3(x-1)-(4x+2+-3(-1x))+7=0
We use the square of the difference formula
3(x-1)-(4x+2-3(-1x))+7=0
We multiply parentheses
3x-(4x+2-3(-1x))-3+7=0
We calculate terms in parentheses: -(4x+2-3(-1x)), so:We add all the numbers together, and all the variables
4x+2-3(-1x)
determiningTheFunctionDomain 4x-3(-1x)+2
We multiply parentheses
4x+3x+2
We add all the numbers together, and all the variables
7x+2
Back to the equation:
-(7x+2)
3x-(7x+2)+4=0
We get rid of parentheses
3x-7x-2+4=0
We add all the numbers together, and all the variables
-4x+2=0
We move all terms containing x to the left, all other terms to the right
-4x=-2
x=-2/-4
x=1/2
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