3(x+(x+1)+(x+2))=72

Solution for 3(x+(x+1)+(x+2))=72 equation:

Simplifying
3(x + (x + 1) + (x + 2)) = 72

Reorder the terms:
3(x + (1 + x) + (x + 2)) = 72

Remove parenthesis around (1 + x)
3(x + 1 + x + (x + 2)) = 72

Reorder the terms:
3(x + 1 + x + (2 + x)) = 72

Remove parenthesis around (2 + x)
3(x + 1 + x + 2 + x) = 72

Reorder the terms:
3(1 + 2 + x + x + x) = 72

Combine like terms: 1 + 2 = 3
3(3 + x + x + x) = 72

Combine like terms: x + x = 2x
3(3 + 2x + x) = 72

Combine like terms: 2x + x = 3x
3(3 + 3x) = 72
(3 * 3 + 3x * 3) = 72
(9 + 9x) = 72

Solving
9 + 9x = 72

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 9x = 72 + -9

Combine like terms: 9 + -9 = 0
0 + 9x = 72 + -9
9x = 72 + -9

Combine like terms: 72 + -9 = 63
9x = 63

Divide each side by '9'.
x = 7

Simplifying
x = 7