3(x*x)=18x+4

Solution for 3(x*x)=18x+4 equation:

3(x*x)=18x+4

We move all terms to the left:

3(x*x)-(18x+4)=0

We add all the numbers together, and all the variables

3(+x*x)-(18x+4)=0

We multiply parentheses

3x^2-(18x+4)=0

We get rid of parentheses

3x^2-18x-4=0

a = 3; b = -18; c = -4;
Δ = b2-4ac
Δ = -182-4·3·(-4)
Δ = 372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{372}=\sqrt{4*93}=\sqrt{4}*\sqrt{93}=2\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{93}}{2*3}=\frac{18-2\sqrt{93}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{93}}{2*3}=\frac{18+2\sqrt{93}}{6}
$