3(w-5)-(1-w)=3-3(4-w)

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Solution for 3(w-5)-(1-w)=3-3(4-w) equation: 



3(w-5)-(1-w)=3-3(4-w)

We move all terms to the left:

3(w-5)-(1-w)-(3-3(4-w))=0

We add all the numbers together, and all the variables

3(w-5)-(-1w+1)-(3-3(-1w+4))=0

We multiply parentheses

3w-(-1w+1)-(3-3(-1w+4))-15=0

We get rid of parentheses

3w+1w-(3-3(-1w+4))-1-15=0



We calculate terms in parentheses: -(3-3(-1w+4)), so:

3-3(-1w+4)

determiningTheFunctionDomain
-3(-1w+4)+3

We multiply parentheses

3w-12+3

We add all the numbers together, and all the variables

3w-9

Back to the equation:

-(3w-9)



We add all the numbers together, and all the variables

4w-(3w-9)-16=0

We get rid of parentheses

4w-3w+9-16=0

We add all the numbers together, and all the variables

w-7=0

We move all terms containing w to the left, all other terms to the right

w=7

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