3(w-2)=2w+2-5(-3w-2)

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Solution for 3(w-2)=2w+2-5(-3w-2) equation: 



3(w-2)=2w+2-5(-3w-2)

We move all terms to the left:

3(w-2)-(2w+2-5(-3w-2))=0

We multiply parentheses

3w-(2w+2-5(-3w-2))-6=0



We calculate terms in parentheses: -(2w+2-5(-3w-2)), so:

2w+2-5(-3w-2)

determiningTheFunctionDomain
2w-5(-3w-2)+2

We multiply parentheses

2w+15w+10+2

We add all the numbers together, and all the variables

17w+12

Back to the equation:

-(17w+12)



We get rid of parentheses

3w-17w-12-6=0

We add all the numbers together, and all the variables

-14w-18=0

We move all terms containing w to the left, all other terms to the right

-14w=18

w=18/-14

w=-1+2/7

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