3(w+5)=27+2w

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Solution for 3(w+5)=27+2w equation: 



3(w+5)=27+2w

We move all terms to the left:

3(w+5)-(27+2w)=0

We add all the numbers together, and all the variables

3(w+5)-(2w+27)=0

We multiply parentheses

3w-(2w+27)+15=0

We get rid of parentheses

3w-2w-27+15=0

We add all the numbers together, and all the variables

w-12=0

We move all terms containing w to the left, all other terms to the right

w=12

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