3(w+5)+w+6=-2(w-4)

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Solution for 3(w+5)+w+6=-2(w-4) equation: 



3(w+5)+w+6=-2(w-4)

We move all terms to the left:

3(w+5)+w+6-(-2(w-4))=0

We add all the numbers together, and all the variables

w+3(w+5)-(-2(w-4))+6=0

We multiply parentheses

w+3w-(-2(w-4))+15+6=0



We calculate terms in parentheses: -(-2(w-4)), so:

-2(w-4)

We multiply parentheses

-2w+8

Back to the equation:

-(-2w+8)



We add all the numbers together, and all the variables

4w-(-2w+8)+21=0

We get rid of parentheses

4w+2w-8+21=0

We add all the numbers together, and all the variables

6w+13=0

We move all terms containing w to the left, all other terms to the right

6w=-13

w=-13/6

w=-2+1/6

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