3(w+2)=-6(3w-4)+9w

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Solution for 3(w+2)=-6(3w-4)+9w equation: 



3(w+2)=-6(3w-4)+9w

We move all terms to the left:

3(w+2)-(-6(3w-4)+9w)=0

We multiply parentheses

3w-(-6(3w-4)+9w)+6=0



We calculate terms in parentheses: -(-6(3w-4)+9w), so:

-6(3w-4)+9w

We add all the numbers together, and all the variables

9w-6(3w-4)

We multiply parentheses

9w-18w+24

We add all the numbers together, and all the variables

-9w+24

Back to the equation:

-(-9w+24)



We get rid of parentheses

3w+9w-24+6=0

We add all the numbers together, and all the variables

12w-18=0

We move all terms containing w to the left, all other terms to the right

12w=18

w=18/12

w=1+1/2

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