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3(w+2)-w=2(w-1)+2
We move all terms to the left:
3(w+2)-w-(2(w-1)+2)=0
We add all the numbers together, and all the variables
-1w+3(w+2)-(2(w-1)+2)=0
We multiply parentheses
-1w+3w-(2(w-1)+2)+6=0
We calculate terms in parentheses: -(2(w-1)+2), so:We add all the numbers together, and all the variables
2(w-1)+2
We multiply parentheses
2w-2+2
We add all the numbers together, and all the variables
2w
Back to the equation:
-(2w)
6!=0
There is no solution for this equation
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