3(w+2)+2(w+5)=41

Solution for 3(w+2)+2(w+5)=41 equation:

Simplifying
3(w + 2) + 2(w + 5) = 41

Reorder the terms:
3(2 + w) + 2(w + 5) = 41
(2 * 3 + w * 3) + 2(w + 5) = 41
(6 + 3w) + 2(w + 5) = 41

Reorder the terms:
6 + 3w + 2(5 + w) = 41
6 + 3w + (5 * 2 + w * 2) = 41
6 + 3w + (10 + 2w) = 41

Reorder the terms:
6 + 10 + 3w + 2w = 41

Combine like terms: 6 + 10 = 16
16 + 3w + 2w = 41

Combine like terms: 3w + 2w = 5w
16 + 5w = 41

Solving
16 + 5w = 41

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 5w = 41 + -16

Combine like terms: 16 + -16 = 0
0 + 5w = 41 + -16
5w = 41 + -16

Combine like terms: 41 + -16 = 25
5w = 25

Divide each side by '5'.
w = 5

Simplifying
w = 5