3(v-5)-4=-4(-6+4v)-9v

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Solution for 3(v-5)-4=-4(-6+4v)-9v equation: 



3(v-5)-4=-4(-6+4v)-9v

We move all terms to the left:

3(v-5)-4-(-4(-6+4v)-9v)=0

We add all the numbers together, and all the variables

3(v-5)-(-4(4v-6)-9v)-4=0

We multiply parentheses

3v-(-4(4v-6)-9v)-15-4=0



We calculate terms in parentheses: -(-4(4v-6)-9v), so:

-4(4v-6)-9v

We add all the numbers together, and all the variables

-9v-4(4v-6)

We multiply parentheses

-9v-16v+24

We add all the numbers together, and all the variables

-25v+24

Back to the equation:

-(-25v+24)



We add all the numbers together, and all the variables

3v-(-25v+24)-19=0

We get rid of parentheses

3v+25v-24-19=0

We add all the numbers together, and all the variables

28v-43=0

We move all terms containing v to the left, all other terms to the right

28v=43

v=43/28

v=1+15/28

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