3(v-2)-5=-2(v+2)

Solution for 3(v-2)-5=-2(v+2) equation:

3(v-2)-5=-2(v+2)

We move all terms to the left:

3(v-2)-5-(-2(v+2))=0

We multiply parentheses

3v-(-2(v+2))-6-5=0


We calculate terms in parentheses: -(-2(v+2)), so:

-2(v+2)

We multiply parentheses

-2v-4

Back to the equation:

-(-2v-4)


We add all the numbers together, and all the variables

3v-(-2v-4)-11=0

We get rid of parentheses

3v+2v+4-11=0

We add all the numbers together, and all the variables

5v-7=0

We move all terms containing v to the left, all other terms to the right

5v=7

v=7/5

v=1+2/5