3(v-2)+5=(2(3v)-5)

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Solution for 3(v-2)+5=(2(3v)-5) equation: 



3(v-2)+5=(2(3v)-5)

We move all terms to the left:

3(v-2)+5-((2(3v)-5))=0

We multiply parentheses

3v-((23v-5))-6+5=0



We calculate terms in parentheses: -((23v-5)), so:

(23v-5)

We get rid of parentheses

23v-5

Back to the equation:

-(23v-5)



We add all the numbers together, and all the variables

3v-(23v-5)-1=0

We get rid of parentheses

3v-23v+5-1=0

We add all the numbers together, and all the variables

-20v+4=0

We move all terms containing v to the left, all other terms to the right

-20v=-4

v=-4/-20

v=1/5

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