3(v-1)-9=-4(-6v+2)-9v

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Solution for 3(v-1)-9=-4(-6v+2)-9v equation: 



3(v-1)-9=-4(-6v+2)-9v

We move all terms to the left:

3(v-1)-9-(-4(-6v+2)-9v)=0

We multiply parentheses

3v-(-4(-6v+2)-9v)-3-9=0



We calculate terms in parentheses: -(-4(-6v+2)-9v), so:

-4(-6v+2)-9v

We add all the numbers together, and all the variables

-9v-4(-6v+2)

We multiply parentheses

-9v+24v-8

We add all the numbers together, and all the variables

15v-8

Back to the equation:

-(15v-8)



We add all the numbers together, and all the variables

3v-(15v-8)-12=0

We get rid of parentheses

3v-15v+8-12=0

We add all the numbers together, and all the variables

-12v-4=0

We move all terms containing v to the left, all other terms to the right

-12v=4

v=4/-12

v=-1/3

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