3(v+4)=-2(6v-4)+9v

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Solution for 3(v+4)=-2(6v-4)+9v equation: 



3(v+4)=-2(6v-4)+9v

We move all terms to the left:

3(v+4)-(-2(6v-4)+9v)=0

We multiply parentheses

3v-(-2(6v-4)+9v)+12=0



We calculate terms in parentheses: -(-2(6v-4)+9v), so:

-2(6v-4)+9v

We add all the numbers together, and all the variables

9v-2(6v-4)

We multiply parentheses

9v-12v+8

We add all the numbers together, and all the variables

-3v+8

Back to the equation:

-(-3v+8)



We get rid of parentheses

3v+3v-8+12=0

We add all the numbers together, and all the variables

6v+4=0

We move all terms containing v to the left, all other terms to the right

6v=-4

v=-4/6

v=-2/3

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