3(v+2)-v=2(v-1+5

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Solution for 3(v+2)-v=2(v-1+5 equation: 



3(v+2)-v=2(v-1+5

We move all terms to the left:

3(v+2)-v-(2(v-1+5)=0

We add all the numbers together, and all the variables

3(v+2)-v-(2(v+4)=0

We add all the numbers together, and all the variables

-1v+3(v+2)-(2(v+4)=0

We multiply parentheses

-1v+3v-(2(v+4)+6=0

We add all the numbers together, and all the variables

2v-(2(v+4)+6=0

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