3(v+1)+7=3(v-2)+2v

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Solution for 3(v+1)+7=3(v-2)+2v equation: 



3(v+1)+7=3(v-2)+2v

We move all terms to the left:

3(v+1)+7-(3(v-2)+2v)=0

We multiply parentheses

3v-(3(v-2)+2v)+3+7=0



We calculate terms in parentheses: -(3(v-2)+2v), so:

3(v-2)+2v

We add all the numbers together, and all the variables

2v+3(v-2)

We multiply parentheses

2v+3v-6

We add all the numbers together, and all the variables

5v-6

Back to the equation:

-(5v-6)



We add all the numbers together, and all the variables

3v-(5v-6)+10=0

We get rid of parentheses

3v-5v+6+10=0

We add all the numbers together, and all the variables

-2v+16=0

We move all terms containing v to the left, all other terms to the right

-2v=-16

v=-16/-2

v=+8

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