3(v+1)+2v=5(v-1)=5

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Solution for 3(v+1)+2v=5(v-1)=5 equation: 



3(v+1)+2v=5(v-1)=5

We move all terms to the left:

3(v+1)+2v-(5(v-1))=0

We add all the numbers together, and all the variables

2v+3(v+1)-(5(v-1))=0

We multiply parentheses

2v+3v-(5(v-1))+3=0



We calculate terms in parentheses: -(5(v-1)), so:

5(v-1)

We multiply parentheses

5v-5

Back to the equation:

-(5v-5)



We add all the numbers together, and all the variables

5v-(5v-5)+3=0

We get rid of parentheses

5v-5v+5+3=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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