3(u-8)+6(u-19)=6

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Solution for 3(u-8)+6(u-19)=6 equation: 



3(u-8)+6(u-19)=6

We move all terms to the left:

3(u-8)+6(u-19)-(6)=0

We multiply parentheses

3u+6u-24-114-6=0

We add all the numbers together, and all the variables

9u-144=0

We move all terms containing u to the left, all other terms to the right

9u=144

u=144/9

u=16

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