3(u-3)=-9u+39

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Solution for 3(u-3)=-9u+39 equation:



3(u-3)=-9u+39
We move all terms to the left:
3(u-3)-(-9u+39)=0
We multiply parentheses
3u-(-9u+39)-9=0
We get rid of parentheses
3u+9u-39-9=0
We add all the numbers together, and all the variables
12u-48=0
We move all terms containing u to the left, all other terms to the right
12u=48
u=48/12
u=4

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