3(u-2)=7u+6-2(-7u-1)

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Solution for 3(u-2)=7u+6-2(-7u-1) equation: 



3(u-2)=7u+6-2(-7u-1)

We move all terms to the left:

3(u-2)-(7u+6-2(-7u-1))=0

We multiply parentheses

3u-(7u+6-2(-7u-1))-6=0



We calculate terms in parentheses: -(7u+6-2(-7u-1)), so:

7u+6-2(-7u-1)

determiningTheFunctionDomain
7u-2(-7u-1)+6

We multiply parentheses

7u+14u+2+6

We add all the numbers together, and all the variables

21u+8

Back to the equation:

-(21u+8)



We get rid of parentheses

3u-21u-8-6=0

We add all the numbers together, and all the variables

-18u-14=0

We move all terms containing u to the left, all other terms to the right

-18u=14

u=14/-18

u=-7/9

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