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3(u-2)=3u+4-2(-8u-4)
We move all terms to the left:
3(u-2)-(3u+4-2(-8u-4))=0
We multiply parentheses
3u-(3u+4-2(-8u-4))-6=0
We calculate terms in parentheses: -(3u+4-2(-8u-4)), so:We get rid of parentheses
3u+4-2(-8u-4)
determiningTheFunctionDomain 3u-2(-8u-4)+4
We multiply parentheses
3u+16u+8+4
We add all the numbers together, and all the variables
19u+12
Back to the equation:
-(19u+12)
3u-19u-12-6=0
We add all the numbers together, and all the variables
-16u-18=0
We move all terms containing u to the left, all other terms to the right
-16u=18
u=18/-16
u=-1+1/8
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