3(u-2)-9=-3(-6u+1)-6u

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Solution for 3(u-2)-9=-3(-6u+1)-6u equation: 



3(u-2)-9=-3(-6u+1)-6u

We move all terms to the left:

3(u-2)-9-(-3(-6u+1)-6u)=0

We multiply parentheses

3u-(-3(-6u+1)-6u)-6-9=0



We calculate terms in parentheses: -(-3(-6u+1)-6u), so:

-3(-6u+1)-6u

We add all the numbers together, and all the variables

-6u-3(-6u+1)

We multiply parentheses

-6u+18u-3

We add all the numbers together, and all the variables

12u-3

Back to the equation:

-(12u-3)



We add all the numbers together, and all the variables

3u-(12u-3)-15=0

We get rid of parentheses

3u-12u+3-15=0

We add all the numbers together, and all the variables

-9u-12=0

We move all terms containing u to the left, all other terms to the right

-9u=12

u=12/-9

u=-1+1/3

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