3(u-2)-4=-6(-3u+1)-u

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Solution for 3(u-2)-4=-6(-3u+1)-u equation: 



3(u-2)-4=-6(-3u+1)-u

We move all terms to the left:

3(u-2)-4-(-6(-3u+1)-u)=0

We multiply parentheses

3u-(-6(-3u+1)-u)-6-4=0



We calculate terms in parentheses: -(-6(-3u+1)-u), so:

-6(-3u+1)-u

We add all the numbers together, and all the variables

-1u-6(-3u+1)

We multiply parentheses

-1u+18u-6

We add all the numbers together, and all the variables

17u-6

Back to the equation:

-(17u-6)



We add all the numbers together, and all the variables

3u-(17u-6)-10=0

We get rid of parentheses

3u-17u+6-10=0

We add all the numbers together, and all the variables

-14u-4=0

We move all terms containing u to the left, all other terms to the right

-14u=4

u=4/-14

u=-2/7

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