3(u-1)=5u+7-2(-7u-1)

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Solution for 3(u-1)=5u+7-2(-7u-1) equation: 



3(u-1)=5u+7-2(-7u-1)

We move all terms to the left:

3(u-1)-(5u+7-2(-7u-1))=0

We multiply parentheses

3u-(5u+7-2(-7u-1))-3=0



We calculate terms in parentheses: -(5u+7-2(-7u-1)), so:

5u+7-2(-7u-1)

determiningTheFunctionDomain
5u-2(-7u-1)+7

We multiply parentheses

5u+14u+2+7

We add all the numbers together, and all the variables

19u+9

Back to the equation:

-(19u+9)



We get rid of parentheses

3u-19u-9-3=0

We add all the numbers together, and all the variables

-16u-12=0

We move all terms containing u to the left, all other terms to the right

-16u=12

u=12/-16

u=-3/4

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