3(u+7)+4u=35

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Solution for 3(u+7)+4u=35 equation: 



3(u+7)+4u=35

We move all terms to the left:

3(u+7)+4u-(35)=0

We add all the numbers together, and all the variables

4u+3(u+7)-35=0

We multiply parentheses

4u+3u+21-35=0

We add all the numbers together, and all the variables

7u-14=0

We move all terms containing u to the left, all other terms to the right

7u=14

u=14/7

u=2

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