3(u+2)-u=(u-1)+5

Solution for 3(u+2)-u=(u-1)+5 equation:

Simplifying
3(u + 2) + -1u = (u + -1) + 5

Reorder the terms:
3(2 + u) + -1u = (u + -1) + 5
(2 * 3 + u * 3) + -1u = (u + -1) + 5
(6 + 3u) + -1u = (u + -1) + 5

Combine like terms: 3u + -1u = 2u
6 + 2u = (u + -1) + 5

Reorder the terms:
6 + 2u = (-1 + u) + 5

Remove parenthesis around (-1 + u)
6 + 2u = -1 + u + 5

Reorder the terms:
6 + 2u = -1 + 5 + u

Combine like terms: -1 + 5 = 4
6 + 2u = 4 + u

Solving
6 + 2u = 4 + u

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-1u' to each side of the equation.
6 + 2u + -1u = 4 + u + -1u

Combine like terms: 2u + -1u = 1u
6 + 1u = 4 + u + -1u

Combine like terms: u + -1u = 0
6 + 1u = 4 + 0
6 + 1u = 4

Add '-6' to each side of the equation.
6 + -6 + 1u = 4 + -6

Combine like terms: 6 + -6 = 0
0 + 1u = 4 + -6
1u = 4 + -6

Combine like terms: 4 + -6 = -2
1u = -2

Divide each side by '1'.
u = -2

Simplifying
u = -2