3(u+1)+7u=4(u+1)-5

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Solution for 3(u+1)+7u=4(u+1)-5 equation: 



3(u+1)+7u=4(u+1)-5

We move all terms to the left:

3(u+1)+7u-(4(u+1)-5)=0

We add all the numbers together, and all the variables

7u+3(u+1)-(4(u+1)-5)=0

We multiply parentheses

7u+3u-(4(u+1)-5)+3=0



We calculate terms in parentheses: -(4(u+1)-5), so:

4(u+1)-5

We multiply parentheses

4u+4-5

We add all the numbers together, and all the variables

4u-1

Back to the equation:

-(4u-1)



We add all the numbers together, and all the variables

10u-(4u-1)+3=0

We get rid of parentheses

10u-4u+1+3=0

We add all the numbers together, and all the variables

6u+4=0

We move all terms containing u to the left, all other terms to the right

6u=-4

u=-4/6

u=-2/3

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