3(u+)+4=5(u-1)+u

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Solution for 3(u+)+4=5(u-1)+u equation: 



3(u+)+4=5(u-1)+u

We move all terms to the left:

3(u+)+4-(5(u-1)+u)=0

We add all the numbers together, and all the variables

3(+u)-(5(u-1)+u)+4=0

We multiply parentheses

3u-(5(u-1)+u)+4=0



We calculate terms in parentheses: -(5(u-1)+u), so:

5(u-1)+u

We add all the numbers together, and all the variables

u+5(u-1)

We multiply parentheses

u+5u-5

We add all the numbers together, and all the variables

6u-5

Back to the equation:

-(6u-5)



We get rid of parentheses

3u-6u+5+4=0

We add all the numbers together, and all the variables

-3u+9=0

We move all terms containing u to the left, all other terms to the right

-3u=-9

u=-9/-3

u=+3

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