3(t-6)+2=4(t+2-21)

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Solution for 3(t-6)+2=4(t+2-21) equation: 



3(t-6)+2=4(t+2-21)

We move all terms to the left:

3(t-6)+2-(4(t+2-21))=0

We add all the numbers together, and all the variables

3(t-6)-(4(t-19))+2=0

We multiply parentheses

3t-(4(t-19))-18+2=0



We calculate terms in parentheses: -(4(t-19)), so:

4(t-19)

We multiply parentheses

4t-76

Back to the equation:

-(4t-76)



We add all the numbers together, and all the variables

3t-(4t-76)-16=0

We get rid of parentheses

3t-4t+76-16=0

We add all the numbers together, and all the variables

-1t+60=0

We move all terms containing t to the left, all other terms to the right

-t=-60

t=-60/-1

t=+60

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