3(t-5)=3-(4+t)

Solution for 3(t-5)=3-(4+t) equation:

3(t-5)=3-(4+t)

We move all terms to the left:

3(t-5)-(3-(4+t))=0

We add all the numbers together, and all the variables

3(t-5)-(3-(t+4))=0

We multiply parentheses

3t-(3-(t+4))-15=0


We calculate terms in parentheses: -(3-(t+4)), so:

3-(t+4)

determiningTheFunctionDomain
-(t+4)+3

We get rid of parentheses

-t-4+3

We add all the numbers together, and all the variables

-1t-1

Back to the equation:

-(-1t-1)


We get rid of parentheses

3t+1t+1-15=0

We add all the numbers together, and all the variables

4t-14=0

We move all terms containing t to the left, all other terms to the right

4t=14

t=14/4

t=3+1/2