3(t-5)+t=33

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Solution for 3(t-5)+t=33 equation: 



3(t-5)+t=33

We move all terms to the left:

3(t-5)+t-(33)=0

We add all the numbers together, and all the variables

t+3(t-5)-33=0

We multiply parentheses

t+3t-15-33=0

We add all the numbers together, and all the variables

4t-48=0

We move all terms containing t to the left, all other terms to the right

4t=48

t=48/4

t=12

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