3(t-4)=4(2t+1)

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Solution for 3(t-4)=4(2t+1) equation: 



3(t-4)=4(2t+1)

We move all terms to the left:

3(t-4)-(4(2t+1))=0

We multiply parentheses

3t-(4(2t+1))-12=0



We calculate terms in parentheses: -(4(2t+1)), so:

4(2t+1)

We multiply parentheses

8t+4

Back to the equation:

-(8t+4)



We get rid of parentheses

3t-8t-4-12=0

We add all the numbers together, and all the variables

-5t-16=0

We move all terms containing t to the left, all other terms to the right

-5t=16

t=16/-5

t=-3+1/5

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