3(t-4)-5=6(2-t)-2

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Solution for 3(t-4)-5=6(2-t)-2 equation: 



3(t-4)-5=6(2-t)-2

We move all terms to the left:

3(t-4)-5-(6(2-t)-2)=0

We add all the numbers together, and all the variables

3(t-4)-(6(-1t+2)-2)-5=0

We multiply parentheses

3t-(6(-1t+2)-2)-12-5=0



We calculate terms in parentheses: -(6(-1t+2)-2), so:

6(-1t+2)-2

We multiply parentheses

-6t+12-2

We add all the numbers together, and all the variables

-6t+10

Back to the equation:

-(-6t+10)



We add all the numbers together, and all the variables

3t-(-6t+10)-17=0

We get rid of parentheses

3t+6t-10-17=0

We add all the numbers together, and all the variables

9t-27=0

We move all terms containing t to the left, all other terms to the right

9t=27

t=27/9

t=3

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