3(t-4)+6=3(2t-7)

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Solution for 3(t-4)+6=3(2t-7) equation: 



3(t-4)+6=3(2t-7)

We move all terms to the left:

3(t-4)+6-(3(2t-7))=0

We multiply parentheses

3t-(3(2t-7))-12+6=0



We calculate terms in parentheses: -(3(2t-7)), so:

3(2t-7)

We multiply parentheses

6t-21

Back to the equation:

-(6t-21)



We add all the numbers together, and all the variables

3t-(6t-21)-6=0

We get rid of parentheses

3t-6t+21-6=0

We add all the numbers together, and all the variables

-3t+15=0

We move all terms containing t to the left, all other terms to the right

-3t=-15

t=-15/-3

t=+5

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