3(t-4)+6=3(2t-5)

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Solution for 3(t-4)+6=3(2t-5) equation: 



3(t-4)+6=3(2t-5)

We move all terms to the left:

3(t-4)+6-(3(2t-5))=0

We multiply parentheses

3t-(3(2t-5))-12+6=0



We calculate terms in parentheses: -(3(2t-5)), so:

3(2t-5)

We multiply parentheses

6t-15

Back to the equation:

-(6t-15)



We add all the numbers together, and all the variables

3t-(6t-15)-6=0

We get rid of parentheses

3t-6t+15-6=0

We add all the numbers together, and all the variables

-3t+9=0

We move all terms containing t to the left, all other terms to the right

-3t=-9

t=-9/-3

t=+3

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