3(t-3)=(4t-2)5

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Solution for 3(t-3)=(4t-2)5 equation: 



3(t-3)=(4t-2)5

We move all terms to the left:

3(t-3)-((4t-2)5)=0

We multiply parentheses

3t-((4t-2)5)-9=0



We calculate terms in parentheses: -((4t-2)5), so:

(4t-2)5

We multiply parentheses

20t-10

Back to the equation:

-(20t-10)



We get rid of parentheses

3t-20t+10-9=0

We add all the numbers together, and all the variables

-17t+1=0

We move all terms containing t to the left, all other terms to the right

-17t=-1

t=-1/-17

t=1/17

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