3(t-3)-2(2t+3)=5(t+3)

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Solution for 3(t-3)-2(2t+3)=5(t+3) equation: 



3(t-3)-2(2t+3)=5(t+3)

We move all terms to the left:

3(t-3)-2(2t+3)-(5(t+3))=0

We multiply parentheses

3t-4t-(5(t+3))-9-6=0



We calculate terms in parentheses: -(5(t+3)), so:

5(t+3)

We multiply parentheses

5t+15

Back to the equation:

-(5t+15)



We add all the numbers together, and all the variables

-1t-(5t+15)-15=0

We get rid of parentheses

-1t-5t-15-15=0

We add all the numbers together, and all the variables

-6t-30=0

We move all terms containing t to the left, all other terms to the right

-6t=30

t=30/-6

t=-5

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