3(t-3)+7t=5(2t+4)-8

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Solution for 3(t-3)+7t=5(2t+4)-8 equation:



3(t-3)+7t=5(2t+4)-8
We move all terms to the left:
3(t-3)+7t-(5(2t+4)-8)=0
We add all the numbers together, and all the variables
7t+3(t-3)-(5(2t+4)-8)=0
We multiply parentheses
7t+3t-(5(2t+4)-8)-9=0
We calculate terms in parentheses: -(5(2t+4)-8), so:
5(2t+4)-8
We multiply parentheses
10t+20-8
We add all the numbers together, and all the variables
10t+12
Back to the equation:
-(10t+12)
We add all the numbers together, and all the variables
10t-(10t+12)-9=0
We get rid of parentheses
10t-10t-12-9=0
We add all the numbers together, and all the variables
-21!=0
There is no solution for this equation

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