3(t-3)+6=3(2t+6)

Solution for 3(t-3)+6=3(2t+6) equation:

3(t-3)+6=3(2t+6)

We move all terms to the left:

3(t-3)+6-(3(2t+6))=0

We multiply parentheses

3t-(3(2t+6))-9+6=0


We calculate terms in parentheses: -(3(2t+6)), so:

3(2t+6)

We multiply parentheses

6t+18

Back to the equation:

-(6t+18)


We add all the numbers together, and all the variables

3t-(6t+18)-3=0

We get rid of parentheses

3t-6t-18-3=0

We add all the numbers together, and all the variables

-3t-21=0

We move all terms containing t to the left, all other terms to the right

-3t=21

t=21/-3

t=-7