3(t-12)=2(t+6)+14

Solution for 3(t-12)=2(t+6)+14 equation:

3(t-12)=2(t+6)+14

We move all terms to the left:

3(t-12)-(2(t+6)+14)=0

We multiply parentheses

3t-(2(t+6)+14)-36=0


We calculate terms in parentheses: -(2(t+6)+14), so:

2(t+6)+14

We multiply parentheses

2t+12+14

We add all the numbers together, and all the variables

2t+26

Back to the equation:

-(2t+26)


We get rid of parentheses

3t-2t-26-36=0

We add all the numbers together, and all the variables

t-62=0

We move all terms containing t to the left, all other terms to the right

t=62