3(t-10)-2(4t-7)=5-6(5t+4)

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Solution for 3(t-10)-2(4t-7)=5-6(5t+4) equation: 



3(t-10)-2(4t-7)=5-6(5t+4)

We move all terms to the left:

3(t-10)-2(4t-7)-(5-6(5t+4))=0

We multiply parentheses

3t-8t-(5-6(5t+4))-30+14=0



We calculate terms in parentheses: -(5-6(5t+4)), so:

5-6(5t+4)

determiningTheFunctionDomain
-6(5t+4)+5

We multiply parentheses

-30t-24+5

We add all the numbers together, and all the variables

-30t-19

Back to the equation:

-(-30t-19)



We add all the numbers together, and all the variables

-5t-(-30t-19)-16=0

We get rid of parentheses

-5t+30t+19-16=0

We add all the numbers together, and all the variables

25t+3=0

We move all terms containing t to the left, all other terms to the right

25t=-3

t=-3/25

t=-3/25

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