3(t-1)=18-t

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Solution for 3(t-1)=18-t equation: 



3(t-1)=18-t

We move all terms to the left:

3(t-1)-(18-t)=0

We add all the numbers together, and all the variables

3(t-1)-(-1t+18)=0

We multiply parentheses

3t-(-1t+18)-3=0

We get rid of parentheses

3t+1t-18-3=0

We add all the numbers together, and all the variables

4t-21=0

We move all terms containing t to the left, all other terms to the right

4t=21

t=21/4

t=5+1/4

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