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3(t-1)-5(3t-1)=25-6(4t+5)
We move all terms to the left:
3(t-1)-5(3t-1)-(25-6(4t+5))=0
We multiply parentheses
3t-15t-(25-6(4t+5))-3+5=0
We calculate terms in parentheses: -(25-6(4t+5)), so:We add all the numbers together, and all the variables
25-6(4t+5)
determiningTheFunctionDomain -6(4t+5)+25
We multiply parentheses
-24t-30+25
We add all the numbers together, and all the variables
-24t-5
Back to the equation:
-(-24t-5)
-12t-(-24t-5)+2=0
We get rid of parentheses
-12t+24t+5+2=0
We add all the numbers together, and all the variables
12t+7=0
We move all terms containing t to the left, all other terms to the right
12t=-7
t=-7/12
t=-7/12
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