3(t-1)-2(2t+3)=10(3t-4)

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Solution for 3(t-1)-2(2t+3)=10(3t-4) equation: 



3(t-1)-2(2t+3)=10(3t-4)

We move all terms to the left:

3(t-1)-2(2t+3)-(10(3t-4))=0

We multiply parentheses

3t-4t-(10(3t-4))-3-6=0



We calculate terms in parentheses: -(10(3t-4)), so:

10(3t-4)

We multiply parentheses

30t-40

Back to the equation:

-(30t-40)



We add all the numbers together, and all the variables

-1t-(30t-40)-9=0

We get rid of parentheses

-1t-30t+40-9=0

We add all the numbers together, and all the variables

-31t+31=0

We move all terms containing t to the left, all other terms to the right

-31t=-31

t=-31/-31

t=1

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