3(t+6)+2=4(t+2)-21

Solution for 3(t+6)+2=4(t+2)-21 equation:

3(t+6)+2=4(t+2)-21

We move all terms to the left:

3(t+6)+2-(4(t+2)-21)=0

We multiply parentheses

3t-(4(t+2)-21)+18+2=0


We calculate terms in parentheses: -(4(t+2)-21), so:

4(t+2)-21

We multiply parentheses

4t+8-21

We add all the numbers together, and all the variables

4t-13

Back to the equation:

-(4t-13)


We add all the numbers together, and all the variables

3t-(4t-13)+20=0

We get rid of parentheses

3t-4t+13+20=0

We add all the numbers together, and all the variables

-1t+33=0

We move all terms containing t to the left, all other terms to the right

-t=-33

t=-33/-1

t=+33