3(t+3)=5(2t-1)

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Solution for 3(t+3)=5(2t-1) equation: 



3(t+3)=5(2t-1)

We move all terms to the left:

3(t+3)-(5(2t-1))=0

We multiply parentheses

3t-(5(2t-1))+9=0



We calculate terms in parentheses: -(5(2t-1)), so:

5(2t-1)

We multiply parentheses

10t-5

Back to the equation:

-(10t-5)



We get rid of parentheses

3t-10t+5+9=0

We add all the numbers together, and all the variables

-7t+14=0

We move all terms containing t to the left, all other terms to the right

-7t=-14

t=-14/-7

t=+2

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