3(t+2)=4(t-3)

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Solution for 3(t+2)=4(t-3) equation: 



3(t+2)=4(t-3)

We move all terms to the left:

3(t+2)-(4(t-3))=0

We multiply parentheses

3t-(4(t-3))+6=0



We calculate terms in parentheses: -(4(t-3)), so:

4(t-3)

We multiply parentheses

4t-12

Back to the equation:

-(4t-12)



We get rid of parentheses

3t-4t+12+6=0

We add all the numbers together, and all the variables

-1t+18=0

We move all terms containing t to the left, all other terms to the right

-t=-18

t=-18/-1

t=+18

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