3(t+2)=2(2+3t)+4

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Solution for 3(t+2)=2(2+3t)+4 equation: 



3(t+2)=2(2+3t)+4

We move all terms to the left:

3(t+2)-(2(2+3t)+4)=0

We add all the numbers together, and all the variables

3(t+2)-(2(3t+2)+4)=0

We multiply parentheses

3t-(2(3t+2)+4)+6=0



We calculate terms in parentheses: -(2(3t+2)+4), so:

2(3t+2)+4

We multiply parentheses

6t+4+4

We add all the numbers together, and all the variables

6t+8

Back to the equation:

-(6t+8)



We get rid of parentheses

3t-6t-8+6=0

We add all the numbers together, and all the variables

-3t-2=0

We move all terms containing t to the left, all other terms to the right

-3t=2

t=2/-3

t=-2/3

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