3(s-9)=4(s-4)+2

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Solution for 3(s-9)=4(s-4)+2 equation:



3(s-9)=4(s-4)+2
We move all terms to the left:
3(s-9)-(4(s-4)+2)=0
We multiply parentheses
3s-(4(s-4)+2)-27=0
We calculate terms in parentheses: -(4(s-4)+2), so:
4(s-4)+2
We multiply parentheses
4s-16+2
We add all the numbers together, and all the variables
4s-14
Back to the equation:
-(4s-14)
We get rid of parentheses
3s-4s+14-27=0
We add all the numbers together, and all the variables
-1s-13=0
We move all terms containing s to the left, all other terms to the right
-s=13
s=13/-1
s=-13

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